The given sequence is 4, 6, 9, 13, 18, 24. Observing the differences between consecutive terms:
The differences themselves form a sequence: 2, 3, 4, 5, 6, which increases by 1 each time. Following this pattern, the next difference is 7.
Next Term:
24 (last term) + 7 (next difference) = 31
Formula:
The sequence can be represented by the quadratic formula:
[
ext{Term}(n) = frac{n^2 + n + 6}{2} ]
For ( n = 7 ):
[
ext{Term}(7) = frac{7^2 + 7 + 6}{2} = frac{62}{2} = 31 ]
Answer: The next number in the sequence is 31.
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