The given sequence is -2, 4, 0, 8, 8, 24, 40.
The sequence follows a recurrence relation:
[
a(n) = a(n-1) + 2 cdot a(n-2)
]
with initial terms:
[
a(1) = -2, quad a(2) = 4
]
The general term can also be expressed as:
[
a(n) = frac{1}{3} cdot 2^n + frac{8}{3} cdot (-1)^n
]
1. Recurrence Relation: Each term is the sum of the previous term and twice the term before it.
2. Characteristic Equation: Solving (r^2
3. Closed-Form: Combining the exponential solutions gives the explicit formula.
Answer: The sequence follows the recurrence relation (a(n) = a(n-1) + 2a(n-2)) with initial terms (-2) and (4). The nth term is (boxed{frac{2^n + 8(-1)^n}{3}}).
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